🦙 5 2X 3 X 6 5

Factor f(x)=x^3+2x^2-5x-6. Step 1. Factor using the rational roots test. Tap for more steps Step 1.1. If a polynomial function has integer coefficients, then every rational zero will have the form where is a factor of the constant and is a factor of the leading coefficient. Step 1.2.

(5 − 2𝑥)/3 ≤ 𝑥/6 − 5 (5 − 2𝑥)/3 ≤ (𝑥 − 30)/6 6 × (5 − 2𝑥)/3 ≤ x - 30 2(5 - 2x) ≤ x - 30. 10 - 4x ≤ x - 30 - 4x - x ≤ - 30 - 10 - 5x ≤ - 40 - x ≤ (−40)/( 5) - x ≤ −8 Since x is negative, we multiply both sides by −1 & change the s

2x2+3x-6=0 Two solutions were found : x = (-3-√57)/4=-2.637 x = (-3+√57)/4= 1.137 Step by step solution : Step 1 :Equation at the end of step 1 : (2x2 + 3x) - 6 = 0 Step 2 :Trying to -x2+3x-6=0 Two solutions were found : x = (-3-√-15)/-2= (3+i√ 15 )/2= 1.5000-1.9365i x = (-3+√-15)/-2= (3-i√ 15 )/2= 1.5000+1.9365i Step by step ^{A "root" is when y is zero: 2x+1 = 0. Subtract 1 from both sides: 2x = −1. Divide both sides by 2: x = −1/2. And that is the solution: x = −1/2. (You can also see this on the graph) We can also solve Quadratic Polynomials using basic algebra (read that page for an explanation). 2. By experience, or simply guesswork.}

Simplify 6(2x−5) 6 ( 2 x - 5). Tap for more steps Simplify −(x+4) - ( x + 4). Tap for more steps Move all terms containing x x to the left side of the equation. Tap for more steps Move all terms not containing x x to the right side of the equation. Tap for more steps Divide each term in 13x = 26 13 x = 26 by 13 13 and simplify.

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5 2x 3 x 6 5